Multishot (Mechanic)

Multishot is a feature that weapons do not normally possess, but can be added through equipped mods. Multishot adds one or more additional bullets, bolts, or pellets to each shot fired. These additional projectiles do not consume any extra ammunition.

For rifles and pistols, excluding the Bronco, every shot fired has a percent chance to fire an additional bullet or bolt equal to the value listed on the equipped mod. Where the value exceeds 100%, there is a chance to fire a third additional bullet or bolt.

For shotguns and the Bronco pistol, each shot fired is increased by a number of pellets equal to the value listed on the equipped mod. Any fractions are converted into a chance to fire an additional pellet, e.g. a Boar with a 120% multishot mod would fire 13 pellets with a 20% chance to fire a 14th. The average number of pellets fired with each shot can be determined by the following table:

Regardless of the weapon type used, any additional bullets or pellets are identical to those that would otherwise have been fired. They are subject to the same damage calculations and each one includes all of the armor piercing and elemental damage that is associated with that projectile. Multishot projectiles only differ in that they do not share the same cone of fire trajectory as the projectile they are a duplicate of. Therefore, they can miss or hit while their parent projectile would hit or miss, respectively.

For rifles and single shot pistols, fire accuracy is calculated using the following formula:

$$a =\left ( \frac{s_{h}}{s_{f}}\right )*100$$


 * Where $$a$$ = accuracy, $$s_{h}$$ = shots hit (including multishot projectiles), and $$s_{f}$$ = shots fired (not including multishot projectiles).

Because of this, is possible to have a fire accuracy higher than 100% with a rifle or single shot pistol using a multishot mod. For example, if you hit 468 shots and you expelled 342 ammunition in a single mission:

$$a = \left ( \frac{468}{342}\right )*100$$

Therefore, we can conclude the following:

$$a = 136.84\%$$